(1/2)^(2x)-(12/(2x))+32=0

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Solution for (1/2)^(2x)-(12/(2x))+32=0 equation: 



(1/2)^(2x)-(12/(2x))+32=0



Domain of the equation: 2)^2x!=0

x!=0/1

x!=0

x∈R





Domain of the equation: 2x)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

(+1/2)^2x-(+12/2x)+32=0

We get rid of parentheses

(+1/2)^2x-12/2x+32=0

We calculate fractions


((+1*2x)/2^2x*2x)+(-24x)/2^2x*2x)+32=0



We calculate terms in parentheses: +((+1*2x)/2^2x*2x), so:

(+1*2x)/2^2x*2x

We multiply all the terms by the denominator


(+1*2x)

We get rid of parentheses

1*2x

Wy multiply elements

2x

Back to the equation:

+(2x)



We multiply all the terms by the denominator


2x*2^2x*2x)+32+(-24x)=0

Wy multiply elements

8x^4*2-24x)=0

We do not support expression: x^4

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